Kinematics Question 529

Question: A particle is moving on a circular path of radius r with uniform velocity v. The change in velocity when the particle moves from $ P $ to $ Q $ it’s $ (\angle POQ={{40}^{{}^\circ }}) $

Options:

A) $ 2v\cos 40{}^\circ $

B) $ 2v\sin 40{}^\circ $

C) $ 2v\sin 20{}^\circ $

D) $ 2v\cos 20{}^\circ $

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Change in velocity =$ 2v\sin (\theta /2)=2vsin20{}^\circ $



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