Kinematics Question 506
Question: An aeroplane moving horizontally with a speed of 720 km/h drops a food pocket, while flying at a height of 396.9 m.the time taken by a food pocket to reach the ground and it’s horizontal range it’s (Take g = 9.8 m/sec2)[AFMC 2001]
Options:
A) 3 sec and 2000 m
B) 5 sec and 500 m
C) 8 sec and 1500 m
D) 9 sec and 1800 m
Show Answer
Answer:
Correct Answer: D
Solution:
$ t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2\times 396.9}{9.8}}\tilde{-}9\sec $
and $ u=720km/hr=200m/s $ $ R=u\times t=200\times 9=1800m $
