Kinematics Question 505
Question: A body is thrown horizontally from the top of a tower of height 5 m.It touches the ground at a distance of 10 m from the foot of the tower.The initial velocity of the body is ${(g = 10 ms^2)}$ [EAMCET (Engg.) 2000]
Options:
A) $ 2.5ms^{1} $
B)$ 5ms^{1} $
C) $ 10ms^{1} $
D) $ 20ms^{1} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ S=u\times \sqrt{\frac{2h}{g}} $
therefore $ 10=u\sqrt{2\times \frac{5}{10}} $
therefore $ u=10m/s $
