Kinematics Question 485

Question: A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/sec. A plumb bob is suspended from the roof of the car by a light rigid rod of length 1.00 m. The angle made by the rod with track it’s [IIT 1992]

Options:

A) Zero

B) $ 30^{o} $

C) $ 45^{o} $

D) $ 60^{o} $

Show Answer

Answer:

Correct Answer: C

Solution:

$ \tan \theta =\frac{v^{2}/r}{g}=\frac{v^{2}}{rg} $

$ \theta ={{\tan }^{-1}}( \frac{v^{2}}{rg} ) $

$ ={{\tan }^{-1}}( \frac{10\times 10}{10\times 10} ) $

$ \theta ={{\tan }^{-1}}(1)=45{}^\circ $



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