SATHEE: Kinematics Question 455

Kinematics Question 455

Question: If $\vec{A} \times \vec{B} = (\vec{C} + \vec{D}),$ then select the correct alternative

Options:

A) $\vec{B}$ it’s parallel to $\vec{C} + \vec{D}$

B) $\vec{A}$ is perpendicular to $\vec{C}$

C) component of $\vec{C}$ along $\vec{A} =$ component of $\vec{D}$ along $\vec{A}$

D) component of $\vec{C}$ along $\vec{A} = -$ component of $\vec{D}$ along $\vec{A}$

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Answer:

Correct Answer: D

Solution:

[d] $(\vec{C} + \vec{D})$ is perpendicular to $\vec{A}$

$∴$ $\vec{A} . (\vec{C} + \vec{D}) = 0$ or $\vec{A} . \vec{C} + \vec{A} . \vec{D} = 0$ or A (component of $\vec{C}$ along A) +A (component of $\vec{D}$ along A) = 0 or Component of $\vec{C}$ along A = ? component of $\vec{D}$ along A.

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Kinematics Question 455

Question: If A→×B→=(C→+D→), then select the correct alternative

Options:

Answer:

Solution:

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Question: If $\vec{A} \times \vec{B} = (\vec{C} + \vec{D}),$ then select the correct alternative