Kinematics Question 447

Question: Find a vector of magnitude 5 along BA where coordinates of points A and B are (0, 1, 3) and (1, 4, 6) respectively

Options:

A) $ ( \frac{5}{\sqrt{19}} )[\hat{i}+3\hat{j}+3\hat{k}] $

B) $ -( \frac{5}{\sqrt{19}} )[\hat{i}+3\hat{j}+3\hat{k}] $

C) $ 5[\hat{i}+3\hat{j}+3\hat{k}] $

D) $ -5[\hat{i}+3\hat{j}+3\hat{k}] $

Show Answer

Answer:

Correct Answer: B

Solution:

[b] $ \overset{\to }{\mathop{BA}}=\overset{\to }{\mathop{OA}}-\overset{\to }{\mathop{OB}}=(\hat{j}+3\hat{k})-(\hat{i}+4\hat{j}+6\hat{k}) $

$ =-\hat{i}-3\hat{j}-3\hat{k} $

Unit vector along $ \overset{\to }{\mathop{BA}}=-\hat{i}-3\hat{j}-3\hat{k}/\sqrt{19} $



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