Kinematics Question 418
Question: A particle when thrown, moves such that it passes from same height at 2 and 10 seconds, then this height h it’s:
Options:
A) 5g
B) g
C) 8g
D) 10g
Show Answer
Answer:
Correct Answer: D
Solution:
As the time taken from D to A = 2 sec.
And D $ \to A\to B\to C=10\text{ sec}( given ). $ As ball goes from $ B\to C(\text{u=0, t=4sec}) $
$ v _{c}=0+4g. $
As it moves from C to D, $ \text{s=ut+}\frac{1}{2}a{{t}^{2}} $
$ s=4g\times 2+\frac{1}{2}g\times 4=10g. $
