Kinematics Question 405

Question: What will be the ratio of the distances moved by a freely falling body from rest on 4th and 5th seconds of journey?

Options:

A) 4 : 5

B) 7 : 9

C) 16 : 25

D) 1 : 1

Show Answer

Answer:

Correct Answer: B

Solution:

$ S _{n}th=u+\frac{a}{2}( 2n-1 ) $

$ \text{So, }\frac{S _{4}}{S _{5}}=\frac{0+\frac{g}{2}( 7 )}{0+\frac{g}{2}( 9 )}=\frac{7}{9} $



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