SATHEE: Kinematics Question 398

Kinematics Question 398

Question: A body is projected vertically upwards. If $t_{1}$ and $t_{2}$ be the times at whichis at height h above the projection while ascending and descending respectively, then h it’s

Options:

A) $\frac{1}{2} g t_{1} t_{2}$

B) $g t_{1} t_{2}$

C) $2 g t_{1} t_{2}$

D) $2 h g$

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Answer:

Correct Answer: A

Solution:

$h = u t_{1} - \frac{1}{2} g t_{1}^{2}$

$Also h=u t_{2} - \frac{1}{2} g t_{2}^{2}$

After simplify above equations, we get $h = \frac{1}{2} g t_{1} t_{2.}$

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Kinematics Question 398

Question: A body is projected vertically upwards. If t1 and t2 be the times at whichis at height h above the projection while ascending and descending respectively, then h it’s

Options:

Answer:

Solution:

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Question: A body is projected vertically upwards. If $t_{1}$ and $t_{2}$ be the times at whichis at height h above the projection while ascending and descending respectively, then h it’s