Kinematics Question 393

Question: A man travelling in a car with a maximum on stat speed of 20m/s watches the friend start off at a distance 100m ahead on a motor cycle with constant acceleration ‘a’. The maximum value of ‘a’ for which the man in the car can reach his friend it’s

Options:

A) $ 2m/s^{2} $

B) $ \text{1 }m/s^{2} $

C) $ 4m/s^{2} $

D) $ 8m{{s}^{-2}} $

Show Answer

Answer:

Correct Answer: A

Solution:

$ v^{2}=u^{2}+2as\text{ 4002a}( 100 );a<2 $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक