Kinematics Question 391

Question: A body A begins to move with initial velocity 2 m/sec and continue to moves at a constant acceleration a.Δt=10 seconds after the body A begins to move a body B departs from the same point with an initial velocity 12 m/sec and moves with the same acceleration a. What is the maximum acceleration a at which the body B can overtake A?

Options:

A) 1m/s2

B) 2m/s2

C) 1/2m/s2

D) 3m/s2

Show Answer

Answer:

Correct Answer: A

Solution:

a=v0v0Δt

On substituting v02 m/s, v  0=12 m/s and Δt=10 sec,

We get, a=1m/s2



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