SATHEE: Kinematics Question 388

Kinematics Question 388

Question: A ship A is moving Westwards with a speed of $10 k m h^{- 1}$ and a ship B 100 km South of A, is moving Northwards with a speed of $10 k m h^{- 1}$ . The time after which the distance between them becomes shortest, it’s

Options:

A) 5h

B) $5 \sqrt{2} h$

C) $10 \sqrt{2} h$

D) 0 h

Show Answer

Answer:

Correct Answer: A

Solution:

$V_{A} = 10 (- \hat{i})$

$V_{B} = 10 (- \hat{j})$

$V_{B A} = 10 \hat{j} + 10 \hat{i}$

$= 10 \sqrt{2} km/h$

$distance OB=100 cos45^{\circ}$

$=50 \sqrt{2} km$

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Kinematics Question 388

Question: A ship A is moving Westwards with a speed of 10kmh−1 and a ship B 100 km South of A, is moving Northwards with a speed of 10kmh−1 . The time after which the distance between them becomes shortest, it’s

Options:

Answer:

Solution:

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Question: A ship A is moving Westwards with a speed of $10 k m h^{- 1}$ and a ship B 100 km South of A, is moving Northwards with a speed of $10 k m h^{- 1}$ . The time after which the distance between them becomes shortest, it’s