Kinematics Question 369

Question: A bike accelerates from rest at a constant rate $ 5m/s^{2} $ for some time after which it decelerates at a constant rate $ 3m/s^{2} $ to come to rest. If the total time elapsed it’s 8 second, the maximum velocity acquired by the bike it’s given by

Options:

A) 5 m/s

B) 10 m/s

C) 12 m/s

D) 15 m/s

Show Answer

Answer:

Correct Answer: D

Solution:

$ {V _{\max }}=0+5t _{1}\text{ }….\text{(i)} $

$ \text{0=}{V _{\max }}-3t _{2}\text{ }….\text{(ii)} $

$ \Rightarrow t _{1}+t _{2}=8={V _{\max }}( \frac{1}{5}+\frac{1}{3} ) $

$ \Rightarrow {{V} _{\max }}=\frac{8\times 15}{8}=15\text{ m/s} $



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