SATHEE: Kinematics Question 369

Kinematics Question 369

Question: A bike accelerates from rest at a constant rate $5 m / s^{2}$ for some time after which it decelerates at a constant rate $3 m / s^{2}$ to come to rest. If the total time elapsed it’s 8 second, the maximum velocity acquired by the bike it’s given by

Options:

A) 5 m/s

B) 10 m/s

C) 12 m/s

D) 15 m/s

Show Answer

Answer:

Correct Answer: D

Solution:

$V_{max} = 0 + 5 t_{1} \dots . (i)$

$0= V_{max} - 3 t_{2} \dots . (ii)$

$\Rightarrow t_{1} + t_{2} = 8 = V_{max} (\frac{1}{5} + \frac{1}{3})$

$\Rightarrow V_{max} = \frac{8 \times 15}{8} = 15 m/s$

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Kinematics Question 369

Question: A bike accelerates from rest at a constant rate $5 m / s^{2}$ for some time after which it decelerates at a constant rate $3 m / s^{2}$ to come to rest. If the total time elapsed it’s 8 second, the maximum velocity acquired by the bike it’s given by

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

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अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Kinematics Question 369

Question: A bike accelerates from rest at a constant rate 5m/s2 for some time after which it decelerates at a constant rate 3m/s2 to come to rest. If the total time elapsed it’s 8 second, the maximum velocity acquired by the bike it’s given by

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: A bike accelerates from rest at a constant rate $5 m / s^{2}$ for some time after which it decelerates at a constant rate $3 m / s^{2}$ to come to rest. If the total time elapsed it’s 8 second, the maximum velocity acquired by the bike it’s given by