Kinematics Question 355

Question: The velocity time graph of the motion of the body is as shown below The total distance travelled by the body during the motion is equal to __.

Options:

A) $ \frac{1}{2}( \text{AD+BE} )\times\text{ OC} $

B) $ \frac{1}{2}( \text{OA+BC} )\times\text{ OC} $

C) $ \frac{1}{2}( \text{OC+AB} )\times\text{ AD} $

D) $ \frac{1}{2}( \text{OA+AB} )\times\text{ BC} $

Show Answer

Answer:

Correct Answer: C

Solution:

distance travelled = area $ \square OABC $

$ =\frac{1}{2}\times ( \text{OC+AB} )\times AD $



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