Kinematics Question 337

Question: The distance time graph of a particle at time makes angles $ 45{}^\circ $ with the time axis. After one second, it makes angle $ 60{}^\circ $ with the time axis.

What is the acceleration of the particle?

Options:

A) $ \sqrt{3}-1 $

B) $ \sqrt{3}+1 $

C) $ \sqrt{3} $

D) 1

Show Answer

Answer:

Correct Answer: A

Solution:

Velocity at time t is $ tan45{}^\circ =1 $ .

Velocity at time $ ( t=1 ) $ is $ tan60{}^\circ =\sqrt{3} $ .

acceleration is change in velocity in one second = $ \sqrt{3}-1. $



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