Kinematics Question 335
Question: A body covers 26, 28, 30, 32 meters in 10th, 11th, 12th and 13th seconds respectively The body
Options:
A) from rest and moves with uniform velocity
B) from rest and moves with uniform acceleration
C) with an initial velocity and moves with uniform acceleration
D) with an initial velocity and moves with uniform velocity
Show Answer
Answer:
Correct Answer: C
Solution:
The distance covered in nth second is $ S _{n}=u+\frac{1}{2}( 2n-1 )a $
Where u it’s initial velocity & a is acceleration $ \text{then 26=u+}\frac{19a}{2}\text{ }…..(i) $
$ \text{28=u+}\frac{21a}{2}\text{ }…..(ii) $
$ \text{30=u+}\frac{23a}{2}\text{ }…..(iii) $
$ \text{32=u+}\frac{25a}{2}\text{ }…..(iv) $
From eqs. (i) and (ii) we get $ u=7m/sec $ , $ a=2m/sec^{2} $
$ \therefore $ The body starts with initial velocity $ u=7m/sec $
and moves with uniform acceleration $ a=2m/sec^{2} $
