SATHEE: Kinematics Question 330

Kinematics Question 330

Question: A 120 m long train is moving towards west with a speed of 10 m/s. A bird flying towards east with a speed of 5 m/s crosses the train. The time taken by the bird to cross the train will be [Manipal 2002]

Options:

A) 2h

B) 2h 40 min

C) 1h 20 min

D) Cannot be estimated with the information given

Show Answer

Answer:

Correct Answer: B

Solution:

Boat covers distance of 16km in a still water in 2 hours. i.e. $v_{B} = \frac{16}{2} = 8 k m / h r$ N

ow velocity of water
$\Rightarrow v_{w} = 4 k m / h r$ .

Time taken for going upstream

$t_{1} = \frac{8}{v_{B} - v_{w}}$

$= \frac{8}{8 - 4} = 2 h r$

(As water current oppose the motion of boat)

Time taken for going down stream $t_{2} = \frac{8}{v_{B} + v_{w}}$

$= \frac{8}{8 + 4} = \frac{8}{12} h r$

(As water current helps the motion of boat)

$∴$ Total time $= t_{1} + t_{2} = (2 + \frac{8}{12}) h r$ or 2hr 40min

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Kinematics Question 330

Question: A 120 m long train is moving towards west with a speed of 10 m/s. A bird flying towards east with a speed of 5 m/s crosses the train. The time taken by the bird to cross the train will be [Manipal 2002]

Options:

Answer:

Solution:

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