Kinematics Question 308
Question: A 120 m long train is moving in a direction with speed 20 m/s. A train B moving with 30 m/s in the opposite direction and 130 m long crosses the first train in a time [CPMT 1996; Kerala PET 2002]
Options:
A) $ 6s $
B) 36 s
C) 38 s
D) None of these
Show Answer
Answer:
Correct Answer: D
Solution:
Total distance $ =130+120=250\ m $ Relative velocity $ =30-(-20)=50\ m/s $ Hence $ t=250/50=5s $