SATHEE: Kinematics Question 283

Kinematics Question 283

Question: The angle between two vectors given by $6 \bar{i} + 6 \bar{j} - 3 \bar{k}$ and $7 \overset{―}{i} + 4 \overset{―}{j} + 4 \overset{―}{k}$ it’s [EAMCET (Engg.) 1999]

Options:

A) $\cos^{- 1} (\frac{1}{\sqrt{3}})$

B) $\cos^{- 1} (\frac{5}{\sqrt{3}})$

C) $\sin^{- 1} (\frac{2}{\sqrt{3}})$

D) $\sin^{- 1} (\frac{\sqrt{5}}{3})$

Show Answer

Answer:

Correct Answer: D

Solution:

$\cos θ = \frac{\vec{A} \vec{B}}{A B} = \frac{42 + 24 - 12}{\sqrt{36 + 36 + 9} \sqrt{49 + 16 + 16}}$

$= \frac{56}{9 \sqrt{71}}$

$\cos θ = \frac{56}{9 \sqrt{71}}$ \ $\sin θ = \frac{\sqrt{5}}{3}$ or $θ = \sin^{- 1} (\frac{\sqrt{5}}{3})$

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Kinematics Question 283

Question: The angle between two vectors given by 6i¯+6j¯−3k¯ and 7i―+4j―+4k― it’s [EAMCET (Engg.) 1999]

Options:

Answer:

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Question: The angle between two vectors given by $6 \bar{i} + 6 \bar{j} - 3 \bar{k}$ and $7 \overset{―}{i} + 4 \overset{―}{j} + 4 \overset{―}{k}$ it’s [EAMCET (Engg.) 1999]