Kinematics Question 270

Question: A particle moves with a velocity $ 6\hat{i}-4\hat{j}+3\hat{k}m/s $ under the influence of a constant force $ \overrightarrow{F}=20\hat{i}+15\hat{j}-5\hat{k}N. $ The instantaneous power applied to the particle is [CBSE PMT 2000]

Options:

A) 35 J/s

B) 45 J/s

C) 25 J/s

D) 195 J/s

Show Answer

Answer:

Correct Answer: B

Solution:

$ P=\vec{F}.\vec{v}=20\times 6+15\times (-4)+(-5)\times 3 $

$ =120-60-15=120-75=45 $ J/s



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