Kinematics Question 246

Question: If a freely falling body travels in the last second a distance equal to the distance travelled by it in the first three second, the time of the travel it’s [Pb. PMT 2004; MH CET 2003]

Options:

A) 6 sec

B) 5 sec

C) 4 sec

D) 3 sec

Show Answer

Answer:

Correct Answer: B

Solution:

The distance traveled in last second. SLast=u+g2(2t1)

=12×9.8(2t1)

=4.9(2t1) and distance traveled in first three second, SThree=0+12×9.8×9=44.1 m According to problem SLast=SThree
4.9(2t1)=44.12t1=9

therefore t = 5 sec.



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