SATHEE: Kinematics Question 24

Kinematics Question 24

Question: A body is at rest under the action of three forces, two of which are ${\vec{F}}_{1} = 4 \hat{i}, {\vec{F}}_{2} = 6 \hat{j},$ the third force is [AMU 1996]

Options:

A) $4 \hat{i} + 6 \hat{j}$

B) $4 \hat{i} - 6 \hat{j}$

C) $- 4 \hat{i} + 6 \hat{j}$

D) $- 4 \hat{i} - 6 \hat{j}$

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Answer:

Correct Answer: D

Solution:

$F_{1} + F_{2} + F_{3} = 0$

therefore $4 \hat{i} + 6 \hat{j} + F_{3} = 0$ ${\vec{F}}_{3} = - 4 \hat{i} - 6 \hat{j}$

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Kinematics Question 24

Question: A body is at rest under the action of three forces, two of which are F→1=4i^,F→2=6j^, the third force is [AMU 1996]

Options:

Answer:

Solution:

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Question: A body is at rest under the action of three forces, two of which are ${\vec{F}}_{1} = 4 \hat{i}, {\vec{F}}_{2} = 6 \hat{j},$ the third force is [AMU 1996]