SATHEE: Kinematics Question 222

Kinematics Question 222

Question: A body thrown vertically upwards with an initial velocity $u$ reaches maximum height in 6 seconds. The ratio of the distances travelled by the body in the first second and the seventh second is [EAMCET (Engg.) 2000]

Options:

A) 1 : 1

B) 11 : 1

C) 1 : 2

D) 1 : 11

Show Answer

Answer:

Correct Answer: B

Solution:

Time of ascent $= \frac{u}{g} = 6 \sec \Rightarrow u = 60 m / s$

distance in first second $h_{f i r s t} = 60 - \frac{g}{2} (2 \times 1 - 1) = 55 m$

distance in seventh second will be equal to the distance in first second of vertical downward motion $h_{s e v e n t h} = \frac{g}{2} (2 \times 1 - 1) = 5 m$

therefore $h_{f i r s t} / h_{s e v e n t h}$

$= 11 : 1$

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Kinematics Question 222

Question: A body thrown vertically upwards with an initial velocity u reaches maximum height in 6 seconds. The ratio of the distances travelled by the body in the first second and the seventh second is [EAMCET (Engg.) 2000]

Options:

Answer:

Solution:

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Question: A body thrown vertically upwards with an initial velocity $u$ reaches maximum height in 6 seconds. The ratio of the distances travelled by the body in the first second and the seventh second is [EAMCET (Engg.) 2000]