SATHEE: Kinematics Question 207

Kinematics Question 207

Question: A body is projected up with a speed $‘ u^{'}$ and the time taken by is $T$ to reach the maximum height $H$ . Pick out the correct statement [EAMCET (Engg.) 1995]

Options:

A) It reaches $H / 2$ in $T / 2$ sec

B) It acquires velocity $u / 2$ in $T / 2 \sec$

C) it’s velocity is $u / 2$ at $H / 2$

D) Same velocity at $2 T$

Show Answer

Answer:

Correct Answer: B

Solution:

At maximum height velocity $v = 0$ We know that $v = u + a t$ ,

hence $0 = u - g T \Rightarrow u = g T$ When $v = \frac{u}{2}$ , then $\frac{u}{2} = u - g t \Rightarrow g t = \frac{u}{2} \Rightarrow g t = \frac{g T}{2} \Rightarrow t = \frac{T}{2}$

Hence at $t = \frac{T}{2}$ , it acquires velocity $\frac{u}{2}$

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Kinematics Question 207

Question: A body is projected up with a speed $‘ u^{'}$ and the time taken by is $T$ to reach the maximum height $H$ . Pick out the correct statement [EAMCET (Engg.) 1995]

Options:

Answer:

Solution:

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सदस्यता

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Kinematics Question 207

Question: A body is projected up with a speed ‘u′ and the time taken by is T to reach the maximum height H . Pick out the correct statement [EAMCET (Engg.) 1995]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: A body is projected up with a speed $‘ u^{'}$ and the time taken by is $T$ to reach the maximum height $H$ . Pick out the correct statement [EAMCET (Engg.) 1995]