SATHEE: Kinematics Question 189

Kinematics Question 189

Question: A body is slipping from an inclined plane of height $h$ and length $l$ . If the angle of inclination it’s $θ$ , the time taken by the body to come from the top to the bottom of this inclined plane is

Options:

A) $\sqrt{\frac{2 h}{g}}$

B) $\sqrt{\frac{2 l}{g}}$

C) $\frac{1}{\sin θ} \sqrt{\frac{2 h}{g}}$

D) $\sin θ \sqrt{\frac{2 h}{g}}$

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Answer:

Correct Answer: C

Solution:

Force down the plane $= m g \sin θ$
$∴$ Acceleration down the plane $= g \sin θ$ Since $l = 0 + \frac{1}{2} g \sin θ t^{2}$
$∴$ $t^{2} = \frac{2 l}{g \sin θ} = \frac{2 h}{g \sin^{2} θ} \Rightarrow t = \frac{1}{\sin θ} \sqrt{\frac{2 h}{g}}$

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Kinematics Question 189

Question: A body is slipping from an inclined plane of height $h$ and length $l$ . If the angle of inclination it’s $θ$ , the time taken by the body to come from the top to the bottom of this inclined plane is

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Kinematics Question 189

Question: A body is slipping from an inclined plane of height h and length l . If the angle of inclination it’s θ , the time taken by the body to come from the top to the bottom of this inclined plane is

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: A body is slipping from an inclined plane of height $h$ and length $l$ . If the angle of inclination it’s $θ$ , the time taken by the body to come from the top to the bottom of this inclined plane is