SATHEE: Kinematics Question 188

Kinematics Question 188

Question: A frictionless wire Ab is fixed on a sphere of radius R. A very small spherical ball slips on this wire. The time taken by this ball to slip from A to b is

Options:

A) $\frac{2 \sqrt{g R}}{g \cos θ}$

B) $2 \sqrt{g R} . \frac{\cos θ}{g}$

C) $2 \sqrt{\frac{R}{g}}$

D) $\frac{g R}{\sqrt{g \cos θ}}$

Show Answer

Answer:

Correct Answer: C

Solution:

Acceleration of body along AB it’s $g \cos θ$ distance travelled in time t sec = $A B = \frac{1}{2} (g \cos θ) t^{2}$ From $Δ A B C, A B = 2 R \cos θ; 2 R \cos θ = \frac{1}{2} g \cos θ t^{2}$

therefore $t^{2} = \frac{4 R}{g}$ or $t = 2 \sqrt{\frac{R}{g}}$

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अगला

Kinematics Question 188

Question: A frictionless wire Ab is fixed on a sphere of radius R. A very small spherical ball slips on this wire. The time taken by this ball to slip from A to b is

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Kinematics Question 188

Question: A frictionless wire Ab is fixed on a sphere of radius R. A very small spherical ball slips on this wire. The time taken by this ball to slip from A to b is

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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