Kinematics Question 187

Question: A mass m slips along the wall of a semispherical surface of radius R. The velocity at the bottom of the surface it’s [MP PMT 1993]

Options:

A) $ \sqrt{Rg} $

B) $ \sqrt{2Rg} $

C) $ 2\sqrt{\pi Rg} $

D) $ \sqrt{\pi Rg} $

Show Answer

Answer:

Correct Answer: B

Solution:

By applying law of conservation of energy $ mgR=\frac{1}{2}mv^{2}\Rightarrow v=\sqrt{2Rg} $



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