Kinematics Question 177

Question: A body a is projected upwards with a velocity of 98m/s . The second body b is projected upwards with the same initial velocity but after 4 sec. Both the bodies will meet after

Options:

A) 6 sec

B) 8 sec

C) 10 sec

D) 12 sec

Show Answer

Answer:

Correct Answer: D

Solution:

Let t be the time of flight of the first body after meeting, then

(t4) sec will be the time of flight of the second body.

Since h1=h2

98t12gt2=98(t4)12g(t4)2

On solving, we get t=12 seconds



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