Kinematics Question 155

Question: A body is in equilibrium under the action of three coplanar forces P, Q and R . Select the correct statement [AFMC 1994]

Options:

A) $ \frac{P}{\sin \alpha }=\frac{Q}{\sin \beta }=\frac{R}{\sin \gamma } $

B) $ \frac{P}{\cos \alpha }=\frac{Q}{\cos \beta }=\frac{R}{\cos \gamma } $

C) $ \frac{P}{\tan \alpha }=\frac{Q}{\tan \beta }=\frac{R}{\tan \gamma } $

D) $ \frac{P}{\sin \beta }=\frac{Q}{\sin \gamma }=\frac{R}{\sin \alpha } $

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Answer:

Correct Answer: A

Solution:

According to Lami’s theorem

$ \frac{P}{\sin \alpha }=\frac{Q}{\sin \beta }=\frac{R}{\sin \gamma } $



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