Kinematics Question 155
Question: A body is in equilibrium under the action of three coplanar forces P, Q and R . Select the correct statement [AFMC 1994]
Options:
A) $ \frac{P}{\sin \alpha }=\frac{Q}{\sin \beta }=\frac{R}{\sin \gamma } $
B) $ \frac{P}{\cos \alpha }=\frac{Q}{\cos \beta }=\frac{R}{\cos \gamma } $
C) $ \frac{P}{\tan \alpha }=\frac{Q}{\tan \beta }=\frac{R}{\tan \gamma } $
D) $ \frac{P}{\sin \beta }=\frac{Q}{\sin \gamma }=\frac{R}{\sin \alpha } $
Correct Answer: A According to Lami’s theorem $ \frac{P}{\sin \alpha }=\frac{Q}{\sin \beta }=\frac{R}{\sin \gamma } $Show Answer
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