Kinematics Question 15

Question: Let $ \overrightarrow{C}=\overrightarrow{A}+\overrightarrow{B} $ then

Options:

A) $ |\overrightarrow{C|} $ is always greater then $ |\overrightarrow{A}| $

B) It’s possible to have $ |\overrightarrow{C}|<|\overrightarrow{A}| $ and $ |\overrightarrow{C}|<|\overrightarrow{B}| $

C) c is always equal to A + B

D) c is never equal to A + B

Show Answer

Answer:

Correct Answer: B

Solution:

$ \vec{C}+\vec{A}=\vec{B} $ .

The value of C lies between $ A-B $ and $ A+B $ \ $ |\vec{C}|\ <\ |\vec{A}|\ \ or\ \ |\vec{C}|\ <\ |\vec{B}| $



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