Kinematics Question 13

Question: A particle has displacement of 12 m towards east and 5 m towards north then 6 m vertically upward. The sum of these displacements it’s [AIIMS 1998]

Options:

A) 12

B) 10.04 m

C) 14.31 m

D) None of these

Show Answer

Answer:

Correct Answer: C

Solution:

$ R=\sqrt{12^{2}+5^{2}+6^{2}}=\sqrt{144+25+36}=\sqrt{205}=14.31\ m $



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