SATHEE: Gravitation Question 67

Gravitation Question 67

Question:What should be the angular speed of earth, so that body lying on equator may appear weightlessness $[(g = 10 m / s^{2}, R = 6400 k m)]$ [Pb. PET 2000]

Options:

A) $[\frac{1}{800} r a d / s]$

B) $[\frac{1}{400} r a d / s]$

C) $[\frac{1}{600} r a d / s]$

D) $[\frac{1}{100} r a d / s]$

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Answer:

Correct Answer: A

Solution:

$[g^{'} = g - ω^{2} R \cos^{2} λ]$

For weightlessness at equator $[λ = 0^{\circ}]$ and $[g^{'} = 0]$

$[0 = g - ω^{2} R]$

Þ $[ω = \sqrt{\frac{g}{R}} = \frac{1}{800} \frac{r a d}{\sec}]$

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Gravitation Question 67

Question:What should be the angular speed of earth, so that body lying on equator may appear weightlessness [(g=10m/s2,R=6400km)] [Pb. PET 2000]

Options:

Answer:

Solution:

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Question:What should be the angular speed of earth, so that body lying on equator may appear weightlessness $[(g = 10 m / s^{2}, R = 6400 k m)]$ [Pb. PET 2000]