Gravitation Question 365

Question: The gravitational field due to a mass distribution is $ [E=K/x^{3}] $ in the x-direction. (K is a constant). Taking the gravitational potential to be zero at infinity, its value at a distance x is

Options:

A) $ [K/x] $

B) $ [K/2x] $

C) $ [K/x^{2}] $

D) $ [K/2x^{2}] $

Show Answer

Answer:

Correct Answer: D

Solution:

  • $ [V=-\int_{\infty }^{x}{Edx=}\int_{\infty }^{x}{K{{x}^{-3}}dx=\frac{K}{2x^{2}}}.] $ .


जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक