Gravitation Question 306

Question: The distance of Neptune and Saturn from the sun is nearly $ [10^{13} and 10^{12}] $ meter respectively. Assuming that they move in circular orbits, their periodic times will be in the ratio

Options:

A) 10

B) 100

C) $ [10\sqrt{10}] $

D) 1000

Show Answer

Answer:

Correct Answer: C

Solution:

  • $ [T^{2}\propto R^{3}] $ (According to Kepler’s law) $ [T_{1}^{2}\propto {{\left( 10^{13} \right)}^{3}}and,,T_{2}^{2}\propto {{\left( 10^{12} \right)}^{3}}] $

    $ [\therefore \frac{T_{1}^{2}}{T_{2}^{2}}={{\left( 10 \right)}^{3}}or,\frac{T_{1}}{T_{2}}=10\sqrt{10}] $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक