Gravitation Question 288
Question: Mass M is divided into two parts xM and $ [(1-x)M] $ . For a given separation, the value of x for which the gravitational attraction between the two pieces becomes maximum is [EAMCET 2001]
Options:
A)$ [\frac{1}{2}] $
B)$ [\frac{3}{5}] $
C) 1
D) 2
Show Answer
Answer:
Correct Answer: A
Solution:
$ [F\propto xm\times (1-x)m=xm^{2}(1-x)] $
For maximum force $ [\frac{dF}{dx}=0] $
Þ$ [\frac{dF}{dx}=m^{2}-2xm^{2}=0\Rightarrow x=1/2] $
