Gravitation Question 243

Question: In a satellite if the time of revolution is T, then K.E. is proportional to [BHU 1995]

Options:

A) $ [\frac{1}{T}] $

B) $ [\frac{1}{T^{2}}] $

C) $ [\frac{1}{T^{3}}] $

D) $ [{{T}^{-2/3}}] $

Show Answer

Answer:

Correct Answer: D

Solution:

v $ [=\sqrt{\frac{GM}{r}}] $ \ $ [K.E.\propto v^{2}\propto \frac{1}{r}] $ and $ [T^{2}\propto r^{3}] $ $ [,K.E.,\propto {{T}^{-2/3}}] $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक