Gravitation Question 222

Question: A rectangular block of size [10cm×8cm×5cm] is kept in three different positions P, Q and R in turn as . In each case, the shaded area is rigidly fixed and a definite force F is applied tangentially to the opposite face to deform the block. The displacement of the upper face will be

Options:

A) Same in all the three cases

B)Maximum in [P] position

C)Maximum in [Q] position

D)Maximum in [R] position

Show Answer

Answer:

Correct Answer: D

Solution:

  • [η=F/Ax/Lx=Lη×FA] In [η] and F are constant, then [xLA] For maximum displacement, area at which force applied should be minimum and vertical side should be maximum. This is given in the R position of rectangular block.


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