Gravitation Question 175

Question: The value of escape velocity on a certain planet is 2 km/s. Then the value of orbital speed for a satellite orbiting close to its surface is [DCE 2005]

Options:

A) 12 km/s

B) 1 km/s

C) $ [\sqrt{2}] $ km/s

D) $ [2\sqrt{2},,km/s] $

Show Answer

Answer:

Correct Answer: C

Solution:

$ [v_{0}=\frac{v_{e}}{\sqrt{2}}=\frac{2}{\sqrt{2}}=\sqrt{2}\ km/s] $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक