SATHEE: Gravitation Question 148

Gravitation Question 148

Question: The escape velocity for the earth is 11.2 km/sec. The mass of another planet is 100 times that of the earth and its radius is 4 times that of the earth. The escape velocity for this planet will be [MP PMT 1999; Pb. PMT 2002]

Options:

A) 112.0 km/s

B) 5.6 km/s

C) 280.0 km/s

D) 56.0 km/s

Show Answer

Answer:

Correct Answer: D

Solution:

Escape velocity $[v = \sqrt{\frac{2, G M}{R}} \Rightarrow \frac{v_{p}}{v_{e}} = \sqrt{\frac{M_{p}}{M_{e}} \times \frac{R_{e}}{R_{p}}}]$ $[\Rightarrow,, v_{p} = 5 v_{e} = 5 \times 11.2 = 56,, k m / s]$

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Gravitation Question 148

Question: The escape velocity for the earth is 11.2 km/sec. The mass of another planet is 100 times that of the earth and its radius is 4 times that of the earth. The escape velocity for this planet will be [MP PMT 1999; Pb. PMT 2002]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Gravitation Question 148

Question: The escape velocity for the earth is 11.2 km/sec. The mass of another planet is 100 times that of the earth and its radius is 4 times that of the earth. The escape velocity for this planet will be [MP PMT 1999; Pb. PMT 2002]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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