Gravitation Question 148

Question: The escape velocity for the earth is 11.2 km/sec. The mass of another planet is 100 times that of the earth and its radius is 4 times that of the earth. The escape velocity for this planet will be [MP PMT 1999; Pb. PMT 2002]

Options:

A) 112.0 km/s

B) 5.6 km/s

C) 280.0 km/s

D) 56.0 km/s

Show Answer

Answer:

Correct Answer: D

Solution:

Escape velocity $ [v=\sqrt{\frac{2,GM}{R}}\Rightarrow \frac{v_{p}}{v_{e}}=\sqrt{\frac{M_{p}}{M_{e}}\times \frac{R_{e}}{R_{p}}}] $ $ [\Rightarrow ,,v_{p}=5v_{e}=5\times 11.2=56,,km/s] $



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