Gravitation Question 135

Question: Radius of orbit of satellite of earth is R. Its kinetic energy is proportional to[BHU 2003; CPMT 2004]

Options:

A) $ [\frac{1}{R}] $

B) $ [\frac{1}{\sqrt{R}}] $

C) R

D) $ [\frac{1}{{{R}^{3/2}}}] $

Show Answer

Answer:

Correct Answer: A

Solution:

$ [K.E.=\frac{GMm}{2R}] $



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