Gravitation Question 135
Question: Radius of orbit of satellite of earth is R. Its kinetic energy is proportional to[BHU 2003; CPMT 2004]
Options:
A) $ [\frac{1}{R}] $
B) $ [\frac{1}{\sqrt{R}}] $
C) R
D) $ [\frac{1}{{{R}^{3/2}}}] $
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Answer:
Correct Answer: A
Solution:
$ [K.E.=\frac{GMm}{2R}] $