SATHEE: Gravitation Question 122

Gravitation Question 122

Question:The gravitational field due to a mass distribution is $[E = K / x^{3}]$ in the x-direction. (K is a constant). Taking the gravitational potential to be zero at infinity, its value at a distance x is [MP PET 1994]

Options:

A) $[K / x]$

B) $[K / 2 x]$

C) $[K / x^{2}]$

D) $[K / 2 x^{2}]$

Show Answer

Answer:

Correct Answer: D

Solution:

Gravitational potential $[= \int_{}^{} I d x = \int_{x}^{\infty} \frac{K}{x^{3}} d x]$ $[= K, (\frac{x^{- 3 + 1}}{- 3 + 1})_{x}^{\infty} = | \frac{- K}{2 x^{2}} |_{x}^{\infty} = \frac{K}{2 x^{2}}]$

पिछला

अगला

Gravitation Question 122

Question:The gravitational field due to a mass distribution is $[E = K / x^{3}]$ in the x-direction. (K is a constant). Taking the gravitational potential to be zero at infinity, its value at a distance x is [MP PET 1994]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Gravitation Question 122

Question:The gravitational field due to a mass distribution is [E=K/x3] in the x-direction. (K is a constant). Taking the gravitational potential to be zero at infinity, its value at a distance x is [MP PET 1994]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Menu

Question:The gravitational field due to a mass distribution is $[E = K / x^{3}]$ in the x-direction. (K is a constant). Taking the gravitational potential to be zero at infinity, its value at a distance x is [MP PET 1994]