Gravitation Question 120

Question: A body of mass m rises to height h = R/5 from the earth’s surface, where R is earth’s radius. If g is acceleration due to gravity at earth’s surface, the increase in potential energy is [CPMT 1989; SCRA 1996; DPMT 2001]

Options:

A) mgh

B) $ [\frac{4}{5}mgh] $

C) $ [\frac{5}{6}mgh] $

D) $ [\frac{6}{7}mgh] $

Show Answer

Answer:

Correct Answer: C

Solution:

$ [\Delta U=\frac{mgh}{1+h/R}] $ Substituting $ [R=5h] $ we get $ [\Delta U=\frac{mgh}{1+1/5}=\frac{5}{6}mgh] $



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