Electrostatics Question 798

Question: Eight drops of mercury of equal radii possessing equal charges combine to form a big drop. Then the capacitance of bigger drop compared to each individual small drop is

Options:

A) 8 times

B) 4 times

C) 2 times

D) 32 times

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Volume of 8 small drops = Volume of big drop

$ 8\times \frac{4}{3}\pi R^{3}=\frac{4}{3}\pi R^{3}\Rightarrow R=2r $

As capacity is proportional to r, hence capacity becomes 2 times.



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