SATHEE: Electrostatics Question 778

Electrostatics Question 778

Question: A charge Q is distributed over two concentric hollow spheres of radii r and R(R>r) such that the surface densities are equal. The potential at the common center is $\frac{1}{4 π ε_{0}}$ times-

Options:

A) $Q [\frac{r + R}{r^{2} + R^{2}}]$

B) $\frac{Q}{2} [\frac{r + R}{r^{2} + R^{2}}]$

C) $2 Q [\frac{r + R}{r^{2} + R^{2}}]$

D) zero

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Answer:

Correct Answer: A

Solution:

[a] $q_{r} + q_{R} = Q$ -.(1) $\frac{q_{r}}{q_{R}} = \frac{4 π r^{2} σ}{4 π R^{2} σ} = \frac{r^{2}}{R^{2}} \Rightarrow \frac{q_{r}}{q_{R}} = \frac{r^{2}}{R^{2}}$ ..(2)

From (1) and (2) $q_{r} = \frac{Q r^{2}}{R^{2} + r^{2}}$

and $q_{R} = \frac{Q R^{2}}{R^{2} + r^{2}}$

So, $V = \frac{q_{r}}{4 π ε_{0} r} + \frac{q_{R}}{4 π ε_{0} R}$

$\Rightarrow V = \frac{Q}{4 π ε_{0}} (\frac{r + R}{r^{2} + R^{2}})$

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Electrostatics Question 778

Question: A charge Q is distributed over two concentric hollow spheres of radii r and R(R>r) such that the surface densities are equal. The potential at the common center is $\frac{1}{4 π ε_{0}}$ times-

Options:

Answer:

Solution:

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Electrostatics Question 778

Question: A charge Q is distributed over two concentric hollow spheres of radii r and R(R>r) such that the surface densities are equal. The potential at the common center is 14πε0 times-

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: A charge Q is distributed over two concentric hollow spheres of radii r and R(R>r) such that the surface densities are equal. The potential at the common center is $\frac{1}{4 π ε_{0}}$ times-