Electrostatics Question 777

Question: Four charges $ q _{1}=2\times {{10}^{-8}}C, $

$ q _{2}=-2\times {{10}^{-8}}C, $

$ q _{3}=-3\times {{10}^{-8}}C $ , $ q _{3}=6\times {{10}^{-8}}C $ are placed at four corners of a square of side $ \sqrt{2} $ m. What is hollow spheres of radii r and R (R > r) such that the common center of the square?

Options:

A) 270 V

B) 300 V

C) Zero

D) 100 V

Show Answer

Answer:

Correct Answer: A

Solution:

[a] Potential at the center O, $ V=k\frac{q}{r} $

$ V=k[ \frac{2\times {{10}^{-8}}}{1}+\frac{-2\times {{10}^{-8}}}{1}+\frac{-3\times {{10}^{-8}}}{1}+\frac{6\times {{10}^{-8}}}{1} ] $

$ V=k\times 3\times {{10}^{-8}}=9\times 10^{9}\times 3\times {{10}^{-8}}volt $

$ =27\times 10=270v $



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