Electrostatics Question 751
Question: There is an infinite straight chain of alternating charges q and -q. The distance between the two neighboring charges is equal to a. Find the interaction energy of any charge with all the other charges.
Options:
A) $ -\frac{2q^{2}}{4\pi {\varepsilon _{0}}a} $
B) $ \frac{2q^{2}{\log _{e}}2}{4\pi {\varepsilon _{0}}a} $
C) $ -\frac{2q^{2}{\log _{e}}2}{4\pi {\varepsilon _{0}}a} $
D) Zero
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ U=2kq^{2}[ -\frac{1}{a}+\frac{1}{2a}-\frac{1}{3a}+\frac{1}{4a}+….. ] $
