Electrostatics Question 700

Question: The electric field intensity just sufficient to balance the earth?s gravitational attraction on an electron will be: (given mass and charge of an electron respectively are $ 9.1\times {{10}^{-31}}kg $ and $ 1.6\times {{10}^{-19}}C. $ )

Options:

A) $ -5.6\times {{10}^{-11}}N/C $

B) $ -4.8\times {{10}^{-15}}N/C $

C) $ -1.6\times {{10}^{-19}}N/C $

D) $ -3.2\times {{10}^{-19}}N/C $

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $ -eE=mg $

$ \vec{E}=-\frac{9.1\times {{10}^{-31}}\times 10}{1.6\times {{10}^{-19}}}=-5.6\times {{10}^{-11}}N/C $



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