SATHEE: Electrostatics Question 693

Electrostatics Question 693

Question: Three identical spheres, each having a charge q And radius R, are kept in such a way that each touches the other two. The magnitude of the electric force any sphere due to the other two is

Options:

A) $\frac{1}{4 π ε_{0}} {(\frac{q}{R})}^{2}$

B) $\frac{\sqrt{3}}{4 π ε_{0}} {(\frac{q}{R})}^{2}$

C) $\frac{\sqrt{3}}{16 π ε_{0}} {(\frac{q}{R})}^{2}$

D) $\frac{\sqrt{5}}{16 π ε_{0}} {(\frac{q}{R})}^{2}$

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Answer:

Correct Answer: C

Solution:

[c] For external points, a charged sphere behaves as if he whole of its charge is concentrated at its center.

Force on A due to B.

$F_{A B} = \frac{1}{4 π ε_{0}} \frac{q^{2}}{{(2 R)}^{2}}$

$= \frac{1}{4 π ε_{0}} \frac{q^{2}}{4 R^{2}} along \vec{B A}$

And force on A due to C,

$F_{A B} = \frac{1}{4 π ε_{0}} \frac{q^{2}}{{(2 R)}^{2}} == \frac{1}{4 π ε_{0}} \frac{q^{2}}{4 R^{2}} along \vec{CA}$

Now as angle between BA and CA is $60^{\circ}$

and $| F_{A B} | = | F_{A C} | = F$

$∴ F_{A} = \sqrt{F^{2} + F^{2} + 2 F F \cos 60} = \sqrt{3} F$

$= \frac{1}{4 π ε_{0}} \frac{\sqrt{3}}{4} {(\frac{q}{R})}^{2}$

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Electrostatics Question 693

Question: Three identical spheres, each having a charge q And radius R, are kept in such a way that each touches the other two. The magnitude of the electric force any sphere due to the other two is

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

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पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Electrostatics Question 693

Question: Three identical spheres, each having a charge q And radius R, are kept in such a way that each touches the other two. The magnitude of the electric force any sphere due to the other two is

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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