Electrostatics Question 68

Question: The diameter of each plate of an air capacitor is $ 4cm $ . To make the capacity of this plate capacitor equal to that of $ 20cm $ diameter sphere, the distance between the plates will be [MP PET 1996]

Options:

A) $ 4\times {{10}^{-3}}m $

B) $ 1\times {{10}^{-3}}m $

C) $ 1cm $

D) $ 1\times {{10}^{-3}}cm $

Show Answer

Answer:

Correct Answer: B

Solution:

Capacity of spherical conductor of 20 cm diameter $ C _{1}=4\pi {\varepsilon _{0}}r=4\pi {\varepsilon _{0}}\times 10 $

Capacity of parallel plate air capacitor $ C _{2}=\frac{{\varepsilon _{0}}A}{d}=\frac{{\varepsilon _{0}}[\pi {{(2)}^{2}}]}{d}=\frac{{\varepsilon _{0}}\times 4\pi }{d} $ Hence $ C _{1}=C _{2} $

therefore $ 40\pi {\varepsilon _{0}}=\frac{4\pi {\varepsilon _{0}}}{d} $

therefore $ d={{10}^{-3}}m $



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