Electrostatics Question 651

Question: A parallel plate capacitor has capacitance C when no dielectric between the plates. Now a slab of dielectric constant K, having same thickness as the separation between the plates is introduced so as to fill one-fourth of the capacitor . The new capacitance will be

Options:

A) (K+1)C4

B) (K+2)C4

C) (K+3)C4

D) KC4

Show Answer

Answer:

Correct Answer: C

Solution:

[c] We can observe that system is equivalent to two capacitors

C1 and C2 in parallel. Capacitance of original capacitor without dipole.

C1=ε0d(3A4)=3ε0A4d

With medium, C2=ε0Ed(A4)=ε0AK4d

C=C1+C2 Or C=3ε0A4d+ε0AK4d=ε0Ad[34+K4] Or C=C4(K+3)

[C=Aε0d]



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